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The relation 3t=sqrt(3x)+6 describe the ...

The relation `3t=sqrt(3x)+6` describe the displacement of a particle in one direction where x is in metres and t in sec.
The displacement, when velocity is zero is

A

24 metres

B

12 metres

C

5 metres

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
D
`3t = sqrt3x + 6 rArr 3x = (3t - 6)^2`
`rArr (dx)/(dt) = v = 1/3 xx 2 (3t - 6 xx 3) = 0`
`rArr t = 2sec`
displacement at t = 2sec is
`x = 1/3 [6-6]^2 = 0`
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