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The motion of a particle along a straigh...

The motion of a particle along a straight line is described by equation : `x = 8 + 12 t - t^3` where `x` is in metre and `t` in second. The retardation of the particle when its velocity becomes zero is.

A

`24ms^(-2)`

B

zero

C

`6ms^(-2)`

D

`12ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`x = 8 + 12t - t^3`
`v = (dx)/(dt) = 12 - 3t^2 = 0 rArr t = 2sec`
`a = (dv)/(dt) = - 6t`
at t = 2sec , ` a= -12m//s^2`
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