A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to
`v(x) = beta x^(-2 n)`
where `beta` and `n` are constant and `x` is the position of the particle. The acceleration of the particle as a function of `x` is given by.

Options

A. `(-2nb^2 x^(-4n-1)`
B. `-2b^2 x^(-2n+1)`
C. `(-2nb^2 e^(-4n+1)`
D. `-2nb^2 x^(-2n-1)`

Answer

A

Explanation

`v(x) = bx^(-2n)`
`a = v (dv)/(dx) = bx^(-2n) {b (-2n)x^(-2n - 1) ) = -2b^2 nx^(-4n - 1)`