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An express train is moving with a veloci...

An express train is moving with a velocity `v_1`. Its driver finds another train is movig on the same track in the same direction with velocity `v_2`. To escape collision, driver applies a retardation a on the train. The minimum time of escaping collision be

A

`t = (v_1 - v_2)/(a)`

B

`t = (v_1^2 - v_2^2)/(2)`

C

none

D

both

Text Solution

Verified by Experts

The correct Answer is:
A

As the train moving in the same direction
Relative velocity ` = v_1 - v_2`
Retardation = a
`v_r = u_r - a_r t`
`rArr t = (v_1 - v_2)/(a)`
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