Particle A moves along X-axis with a uniform velocity of magnitude 10 m/s. Particle B moves with uniform velocity 20 m/s along a direction making an angle of 60° with the positive direction of X-axis as shown in the figure. The relative velocity of B with respect to that A is

Options

A. 10 m/s along X-axis
B. `10sqrt3` m/s along Y-axis (perpendicular to X-axis)
C. `10sqrt5`along the bisection of the velocity of A and B
D. 30 m/s along negative X-axis

Answer

B

Explanation

`vec(V_(BA)) = vecV_B - vecV_A`
` = (20 xx cos 60^@ hati + 20 sin 60^@ hatj) - 10 hati = 10 sqrt3 hatj`