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A particle is projected up with an initi...

A particle is projected up with an initial velocity of `80 ft//sec`. The ball will be at a height of 96ft from the ground after

A

2.0 and 3.0 sec

B

Only at 3.0 sec

C

Only at 2.0 sec

D

After 1 and 2 sec

Text Solution

Verified by Experts

The correct Answer is:
A
`1m = 3.28 ft`
`h = ut - 1/2 g t^2 rArr 96 = 80t - 1/2 xx 32 xx t^2`
`rArr 16t^2 - 80t + 96=0`
`rArr t^2 - 5t + 6 = 0 rArr t = 3 or 2 sec`
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