A body, thrown upwards with some velocity, reaches the maximum height of 20 m . Another body with double the mass thrown up, with double initial velocity will reach a maximum height of

Options

A. 200m
B. 16m
C. 80m
D. 40m

Answer

C

Explanation

`Since `H_(max) prop u^2`
`((H_(max))_1)/((H_(max)_2) = (u^2)/(4u^2) rArr (H_(max)_2) = 4(H_(max))_1`
`(H_(max))_2 = 4 xx 20 = 80m`