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A ball is dropped from top of a tower of 100 m height. Simultaneously another ball was thrown upward from bottom of the tower with a speed of `50 m//s (g = 10m//s^(2))`. They will cross each other after

A

1s

B

2s

C

3s

D

4s

Text Solution

Verified by Experts

The correct Answer is:
B

`h_1 = 1/2 g t^2`
`h_2 = 50t - 1/2 g t^2`
`h_1 + h_2 = 100 rArr 50t = 100 rArr t = 2sec`
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