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Water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap, the instant the first drop touches the ground. How far above the ground is the second drop at that instant. `(g = 10 ms^-2)`

A

2.50 m

B

3.75 m

C

4.00 m

D

1.25 m

Text Solution

Verified by Experts

The correct Answer is:
B

Time taken by 1st drop to reach the ground
`t = sqrt((2h)/(g)) = sqrt((2xx5)/(10)) = 1sec`
As drop falls at regular intervals therefore time difference between any two drops ` = 1/2 sec`
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