A body A is thrown up vertically from the ground with velocity `V_(0)` and another body B is simultaneously dropped from a height H. They meet simultaneously dropped from a height H. They meet at a height `(H)/(2)` if `V_(0)` is equal to

Options

A. `sqrt(2gH)`
B. `sqrt(gH)`
C. `1/2 sqrt(gH)`
D. `sqrt((2g)/(H))`

Answer

B

Explanation

For body A, `u = V_0, a = -g , h = H/2`
`H/2 = V_0 t - 1/2 g t^2`
For Body B
`H/2 = 1/2 g t^2 rArr t = sqrt(H/g)`
`rArr H/2 = V_0 sqrt(H/g) - 1/2 g xx H/g`
`rArr v_0^2 xx H/g = H^2 rArr v_0 = sqrt(gH)`