Same force acts on two bodies of different masses 3 kg and 5 kg initially at rest. The ratio of time required to acquire same final velocity is

Options

A. `5: 3`
B. `25 : 9`
C. `9 : 25`
D. `3 : 5`

Answer

D

Explanation

`t =(v)/(a) rArr t prop (1)/(a) " "[v ="constant"]`
`(t_(1))/(t_(2))=(a_(2))/(a_(1)) = (m_(1))/(m_(2))[F = ma rArr m prop (1)/(a)] therefore (t_(1))/(t_(2)) =(3)/(5)`