An army vehicle of mass 1000 kg is moving with a velocity of `10 m//s` and is acted upon by a forward force of 1000 N due to the engine and a retarding force of 500 N due to friction. What will be its velocity after 10 s

Options

A. 5 m/s
B. 10 m/s
C. 15 m.s
D. 20 m/s

Answer

C

Explanation

`a = (1000 - 500)/(1000) = (1)/(2) =0.5 m//s^(2)`
` u = 10m//s, t = 1 sec `
`v = u + at = 10 + 0.5 xx 10`
`v = 15m//s`