A block of mass kg 5 is moving horizontally at a speed of `1.5 m//s` . A perpendicular force of 5 N acts on it for 4 sec. What will be the distance of the block from the point where the force started acting

Options

A. 10 m
B. 8m
C. 6 m
D. 2 m

Answer

A

Explanation

m = 5kg : u = 1.5 m/s (horizontal )
`a = (5)/(5) = 1 m//s^(2) ` (perpendicular to velocity)
`S_(H) = ut = 1.5 xx 4 =6 m`
`S_(V)= (1)/(2) at^(2) = (1)/(2) xx 1 xx (4)^(2) = 8m`
`S_("net") = sqrt(6^(2) + 8^(2)) = 10m`