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A mass 1 kg is suspended by a thread. It...

A mass 1 kg is suspended by a thread. It is
(i) lifted up with an acceleration `4.9m//s^(2)`
(ii) lowered with an acceleration `4.9m//s^(2)`.
The ratio of the tensions is

A

`3:1`

B

`1:3`

C

`1:2`

D

`2:1`

Text Solution

Verified by Experts

The correct Answer is:
A
`(T_(U))/(T_(D)) = (m(g+a))/(m(g-a)) = (9.8 + 4.9)/(9.8 - 4.9) = (3)/(1)`
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