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If in a stationary lift, a man is standi...

If in a stationary lift, a man is standing with a bucket full of water, having a hole at its bottom. The rate of flow of water through this hole is `R_(0)`. If the lift starts to move up and down with same acceleration and then that rates of flow of water are `R_(u)` and , `R_(d)`, then

A

`R_(0) gt R_(u) gt R_(d)`

B

`R_(u) gt R_(0) gt R_(d)`

C

`R_(d) gt R_(0) gt R_(u)`

D

`R_(u) gt R_(d) gt R_(0)`

Text Solution

Verified by Experts

The correct Answer is:
B
`F_(u) = m(g+a) : F_(d) m(g-a)`
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