A body of mass 0.05 kg is observed to fall with an acceleration of `9.5 ms^(-2)`. The opposing force of air on the body is `(g = 9.8 ms^(-2))`. The opposing force of air on the body is `(g = 9.8ms^(-2))`.

Options

A. 0.015 N
B. 0.15 N
C. 0.030 N
D. Zero

Explanation

To find the opposing force of air on the body, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

### Step-by-Step Solution:

1. **Identify the Given Data:**
- Mass of the body, \( m = 0.05 \, \text{kg} \)
- Acceleration of the body, \( a = 9.5 \, \text{m/s}^2 \)
- Acceleration due to gravity, \( g = 9.8 \, \text{m/s}^2 \)

2. **Calculate the Weight of the Body:**
The weight \( W \) of the body can be calculated using the formula:
\[ W = m \cdot g \]
Substituting the values:
\[ W = 0.05 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 = 0.49 \, \text{N} \]

3. **Determine the Net Force Acting on the Body:**
According to Newton's second law:
\[ F_{\text{net}} = m \cdot a \]
Substituting the values:
\[ F_{\text{net}} = 0.05 \, \text{kg} \cdot 9.5 \, \text{m/s}^2 = 0.475 \, \text{N} \]

4. **Calculate the Opposing Force of Air:**
The net force is the difference between the weight of the body and the opposing force of air \( F_{\text{air}} \):
\[ F_{\text{net}} = W - F_{\text{air}} \]
Rearranging the equation to find \( F_{\text{air}} \):
\[ F_{\text{air}} = W - F_{\text{net}} \]
Substituting the values:
\[ F_{\text{air}} = 0.49 \, \text{N} - 0.475 \, \text{N} = 0.015 \, \text{N} \]

5. **Conclusion:**
The opposing force of air on the body is \( 0.015 \, \text{N} \).