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A rocket of mass 100 kg burns 0.1 kg of ...

A rocket of mass 100 kg burns 0.1 kg of fuel per sec. If velocity of exhaust gas is 1 km/sec, then it lifts with an acceleration of

A

`1000 ms^(-2)`

B

`100 ms^(-2)`

C

`10 ms^(-2)`

D

`1 ms^(-2)`

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The correct Answer is:
To solve the problem of the rocket's acceleration, we can use the principles of momentum and thrust. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Given Data - Mass of the rocket (m) = 100 kg - Rate of fuel consumption (dm/dt) = 0.1 kg/s - Velocity of exhaust gas (v) = 1 km/s = 1000 m/s (conversion from km/s to m/s) ### Step 2: Understand the Thrust Force The thrust force (Ft) generated by the rocket can be calculated using the formula: \[ F_t = v \cdot \frac{dm}{dt} \] Where: - \( v \) is the velocity of the exhaust gas. - \( \frac{dm}{dt} \) is the rate of change of mass (mass flow rate of the exhaust). ### Step 3: Calculate the Thrust Force Substituting the known values into the thrust formula: \[ F_t = 1000 \, \text{m/s} \cdot 0.1 \, \text{kg/s} \] \[ F_t = 100 \, \text{N} \] ### Step 4: Apply Newton's Second Law According to Newton's second law, the net force acting on the rocket is equal to the mass of the rocket multiplied by its acceleration (a): \[ F_{\text{net}} = m \cdot a \] The net force acting on the rocket is the thrust force minus the weight of the rocket (W): \[ F_{\text{net}} = F_t - W \] Where weight \( W = m \cdot g \) (g = acceleration due to gravity, approximately \( 9.81 \, \text{m/s}^2 \)): \[ W = 100 \, \text{kg} \cdot 9.81 \, \text{m/s}^2 = 981 \, \text{N} \] ### Step 5: Set Up the Equation Now, we can set up the equation: \[ F_t - W = m \cdot a \] Substituting the values: \[ 100 \, \text{N} - 981 \, \text{N} = 100 \, \text{kg} \cdot a \] \[ -881 \, \text{N} = 100 \, \text{kg} \cdot a \] ### Step 6: Solve for Acceleration (a) To find the acceleration, rearrange the equation: \[ a = \frac{-881 \, \text{N}}{100 \, \text{kg}} \] \[ a = -8.81 \, \text{m/s}^2 \] ### Conclusion The negative sign indicates that the thrust is not sufficient to lift the rocket against gravity; thus, the rocket does not accelerate upwards. Instead, it experiences a downward acceleration of \( 8.81 \, \text{m/s}^2 \).

To solve the problem of the rocket's acceleration, we can use the principles of momentum and thrust. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Given Data - Mass of the rocket (m) = 100 kg - Rate of fuel consumption (dm/dt) = 0.1 kg/s - Velocity of exhaust gas (v) = 1 km/s = 1000 m/s (conversion from km/s to m/s) ### Step 2: Understand the Thrust Force ...
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