A block of mass M placed on a frictionless horizontal table is pulled by another block of mass m hanging vertically by a massless string passing over a frictionless pulley. The tension in the string is :

Options

A. `(m)/(M+m)g`
B. `(M)/(M+m)g`
C. `(M+m)/(Mm)g`
D. `(Mm)/(M+m)g`

Answer

D

Explanation

`T = m xx a = M xx ((mg)/(M + m)) = (Mmg)/(M + m)`