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Three blocks of masses 4 kg, 2 kg and 1 kg respectively are in contact on a frictionless table as shown in the figure. If a force of `14N` is applied on the 4 kg block, the contact force between the 4 kg and the 2 kg block will be

A

2 N

B

6 N

C

8 N

D

14 N

Text Solution

Verified by Experts

The correct Answer is:
B
`a = (14)/(4+2+1) = 2m//s^(2)`
`14-R = 4 xx 2 rArr R = 6 N`
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