Two spherical objects each of radii R and masses m1 and m2 are suspended using two strings of equal length L as shown in the figure `(R lt lt L)`. The angle, `theta` which mass `m_(2)` makes with the vertical is approximately -

Options

A. `(m_(1)R)/((m_(1)+m_(2))L)`
B. `(2m_(1)R)/((m_(1) +m_(2))L)`
C. `(2m_(2)R)/((m_(1) + m_(2))L)`
D. `(m_(2)R)/((m_(1) + m_(2))L)`

Answer

B

Explanation

Distance of centre of mass from `m_(2) `
`d = (m_(1))/((m_(1) + m_(2)))xx 2R`
`theta = ("distance(d)")/(L) rArr theta = (m_(1))/((m_(1) + m_(2))) xx (2R)/(L)`