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The maximum energy in thermal radiation ...

The maximum energy in thermal radiation from a source occurs at the wavelength 4000Å. The effective temperature of the source

A

7000 K

B

80000 K

C

`10^4` K

D

`10^6` K

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda_m=b/T implies T=(b)/(lambda_m)=(2.93xx10^(-3))/(4000xx10^(-10))`
`7325K ~~ 7000 K` (approx).
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