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A body of area 1cm^2 is heated to a tem...

A body of area `1cm^2` is heated to a temperature 1000K. The amount of energy radiated by the body in 1 s is (Stefan’s constant `sigma = 5.67 xx 10^(-8)Wm^(-2)K^(-4)`)

A

5.67 joule

B

0.567 joule

C

56.7 joule

D

567 joule

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use the Stefan-Boltzmann law, which states that the power radiated by a black body per unit area is proportional to the fourth power of its absolute temperature. The formula for power (P) is given by: \[ P = \sigma \cdot A \cdot T^4 \] Where: - \( P \) is the power in watts (W), - \( \sigma \) is the Stefan-Boltzmann constant (\( 5.67 \times 10^{-8} \, \text{W/m}^2\text{K}^4 \)), - \( A \) is the area in square meters (m²), - \( T \) is the absolute temperature in kelvins (K). ### Step 1: Convert the area from cm² to m² The area given is \( 1 \, \text{cm}^2 \). We need to convert this to square meters: \[ 1 \, \text{cm}^2 = 1 \times 10^{-4} \, \text{m}^2 \] ### Step 2: Use the Stefan-Boltzmann law to calculate the power Now we can substitute the values into the formula: \[ P = \sigma \cdot A \cdot T^4 \] Substituting the values: \[ P = (5.67 \times 10^{-8} \, \text{W/m}^2\text{K}^4) \cdot (1 \times 10^{-4} \, \text{m}^2) \cdot (1000 \, \text{K})^4 \] ### Step 3: Calculate \( (1000 \, \text{K})^4 \) Calculating \( (1000)^4 \): \[ (1000)^4 = 10^{12} \] ### Step 4: Substitute back into the power equation Now substituting \( (1000)^4 \) back into the power equation: \[ P = (5.67 \times 10^{-8}) \cdot (1 \times 10^{-4}) \cdot (10^{12}) \] ### Step 5: Simplify the expression Now we simplify the expression: \[ P = 5.67 \times 10^{-8} \times 10^{-4} \times 10^{12} \] \[ P = 5.67 \times 10^{0} \, \text{W} = 5.67 \, \text{W} \] ### Step 6: Calculate the energy radiated in 1 second Since power is the rate of energy transfer, the energy radiated in 1 second (E) is equal to the power: \[ E = P \cdot t = 5.67 \, \text{W} \cdot 1 \, \text{s} = 5.67 \, \text{J} \] ### Final Answer The amount of energy radiated by the body in 1 second is: \[ \boxed{5.67 \, \text{J}} \]

To solve the problem, we will use the Stefan-Boltzmann law, which states that the power radiated by a black body per unit area is proportional to the fourth power of its absolute temperature. The formula for power (P) is given by: \[ P = \sigma \cdot A \cdot T^4 \] Where: - \( P \) is the power in watts (W), - \( \sigma \) is the Stefan-Boltzmann constant (\( 5.67 \times 10^{-8} \, \text{W/m}^2\text{K}^4 \)), - \( A \) is the area in square meters (m²), ...
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