The energy emitted per second by a black body at `27^(@)C` is 10 J. If the temperature of the black body is increased to `327^(@)C` , the energy emitted per second will be

Options

A. 20 J
B. 40 J
C. 80 J
D. 160 J

Answer

D

Explanation

(Q) = Energy emitted by black body A`sigma T^4 t`
`implies Q prop T^4`
`implies Q_2 =Q_1 ((T_2)/(T_1))^4=10((273+327)/(273+27))^4`
`implies Q_2=10 ((600)/(300))^4 =160 J`.