A sphere at temperature `600 K` is placed in an enviroment to temperature is `200 K`. Its cooling rate is `H`. If its temperature reduced to `400 K` then cooling rate in same enviorment will become

Options

A. `(3//16)H`
B. `(16//3)H`
C. `(9//27)H`
D. `(1//16)H`

Answer

A

Explanation

Rate of cooling `prop (T^4 - T_0^4)`
`implies (H)/(H.)=((T_1^4 -T_0^4)/(T_2^4 -T_0^4))=(((600)^4-(200)^4)/((400)^4-(200)^4)) implies H. =(3)/(16) H`