The tungsten filament of an electric lamp has a surface areaA and a power rating P. If the emissivity of the filament is `varepsilon` and `sigma` is Stefan's constant,the steady temperature of the filament will be:

Options

A. `T=((P)/(A epsilon sigma))^4`
B. `T=((P)/(A epsilon sigma))`
C. `T=((A epsilon sigma)/(P))^(1//4)`
D. `T=((P)/(A epsilon sigma))^(1/4)`

Answer

D

Explanation

Rate of energy (Power) `P=A epsilon sigma T^4`
`T=((P)/(A epsilon sigma))^(1/4)`