A black body is at a temperature of `5760 K`. The energy of radiation emitted by the body at wavelength `250 nm` is `U_(1)` at wavelength `500 nm` is `U_(2)` and that at `1000 nm` is `U_(3)`. Wien's consant, `b = 2.88 xx 10^(6) nmK`. Which of the following is correct?

Options

A. `U_1=0`
B. `U_3=0`
C. `U_1 gt U_2`
D. `U_2 gt U_1`

Answer

D

Explanation

Maximum amount of emitted radiation corresponding to `lambda_m=b/T`
`lambda_m=(2.88 xx 10^6 nmK)/(5760K)=500 nm`

From the graph `U_1 lt U_2 gt U_3`.