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The power radiated by a black body is P,...

The power radiated by a black body is P, and it radiates maximum energy around the wavelength `lambda_(0)`. If the temperature of the black body is now changed so that it radiates maximum energy around a wavelength `3lambda_(0)//4`, the power radiated by it will increase by a factor of

A

`3/4`

B

`4/3`

C

`(256)/(81)`

D

`(81)/(256)`

Text Solution

Verified by Experts

The correct Answer is:
C

Power radiated (P)=`sigma AT^4`
`implies P prop T^4`
From Wein’s law : `T lambda_(m)=b implies T prop (1)/(lambda_m)`
`P prop ((1)/(lambda_m))^4 implies (P_2)/(P_1)=((lambda_(m_2))/(lambda_(m_1)))^4`
`(P_2)/(P_1)=((lambda_0)/(3/4 lambda_0))^3 implies (nP)/(P)=(256)/(81) implies n = (256)/(81)`
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