Two particles A and B execute simple harmonic motions of period T and `5T//4`. They start from mean position. The phase difference between them when the particle A complete an oscillation will be

Options

A. `pi//2`
B. `0`
C. `2pi//5`
D. `pi//4`

Answer

C

Explanation

Phase difference `(Deltaphi)=(2pi)/(T)xx`time difference
`Deltaphi_(1)=(2pi)/(T)xxT=2pi`
`Deltaphi_(2)=(2pi)/((5T)/(4))*T=(8pi)/(5)`
`therefore Delta phi=Deltaphi_(1)-Deltaphi_(2)=2pi-(8pi)/(5) implies Deltaphi=(2pi)/(5)`.