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The displacement of a particle executing...

The displacement of a particle executing simple harmonic motion is given by
`y=A_(0)+Asinomegat+Bcosomegat`
Then the amplitude of its oscillation is given by :

A

`A+B`

B

`A_(0)+sqrt(A^(2)+B^(2))`

C

`sqrt(A^(2)+B^(2))`

D

`sqrt(A_(0)^(2)+(A+B)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C

`y=A_(0)+Asinomegat+Bcosomegat`
Hence, 2 SHM.s are super imposed with phase difference of `pi/2`
Amplitude `=sqrt(A^(2)+B^(2)+2ABcosDeltaphi)" "[because Deltaphi=(pi)/(2)]`
`=sqrt(A^(2)+B^(2))`.
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