Home
Class 11
PHYSICS
The instantaneous displacement of a simp...

The instantaneous displacement of a simple pendulum oscillator is given by `x= A cos (omegat+ pi / 4 )`Its speed will be maximum at time

A

`(pi)/(4omega)`

B

`(pi)/(2omega)`

C

`(pi)/(omega)`

D

`(2pi)/(omega)`

Text Solution

Verified by Experts

The correct Answer is:
A

`x=Acos(omegat+(pi)/(4))`
`v(dx)/(dt)=-Aomegasin(omegat+(pi)/(4))`
For maximum speed-
`sin(omegat+(pi)/(4))=1 implies omegat+(pi)/(4)=(pi)/(2)`
`implies omegat=(pi)/(2)-(pi)/(4)implies t=(pi)/(4omega)`.
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    ERRORLESS|Exercise NCERT BASED QUESTIONS (Acceleration of Simple Harmonic Motion)|11 Videos
  • SIMPLE HARMONIC MOTION

    ERRORLESS|Exercise NCERT BASED QUESTIONS (Energy of Simple Harmonic Motion)|18 Videos
  • SIMPLE HARMONIC MOTION

    ERRORLESS|Exercise Assertion & Reason|15 Videos
  • ROTATIONAL MOTION

    ERRORLESS|Exercise Assertion & Reason|25 Videos
  • SURFACE TENSION

    ERRORLESS|Exercise ASSERTION & REASON|11 Videos

Similar Questions

Explore conceptually related problems

The displacement of a simple harmonic oscillator is given by x = 4 cos (2pit+pi//4)m . Then velocity of the oscillator at t = 2 s is

The displacement of a particle is given by x = cos^(2) omegat. The motion is

The displacement equation of a simple harmonic oscillator is given by y=A sin omegat-Bcos omegat The amplitude of the oscillator will be

The displacement x of a particle in motion is given in terms of time by x(x-4) =1 -5 cos omegat

The time period of a simple pendulum oscillating in a freely falling lift is

If a simple pendulum oscillates in water instead of air then the time period will -

The instantaneous displacement x of a particle executing simple harmonic motion is given by x=a_1sinomegat+a_2cos(omegat+(pi)/(6)) . The amplitude A of oscillation is given by

The angular displacement of a simple pendulum is increased from 2^(@) to 4^(@) . Its frequency of oscillation