Home
Class 11
PHYSICS
The maximum velocity of a particle execu...

The maximum velocity of a particle executing S.H.M. is u. If the amplitude is doubled and the time period of oscillation decreases to (1/3) of its original value, then the maximum velocity will be

A

18 v

B

12 v

C

6 v

D

3 v

Text Solution

Verified by Experts

The correct Answer is:
C
`v_(max)=Aomega=(2piA)/(T) implies vprop(A)/(T)`
`(v_(1))/(v_(2))=(A_(1))/(A_(2))xx(T_(2))/(T_(1))=(1)/(2)xx(1)/(3)`
`implies v_(2)=6v_(1)=6v`.
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    ERRORLESS|Exercise NCERT BASED QUESTIONS (Acceleration of Simple Harmonic Motion)|11 Videos

  • SIMPLE HARMONIC MOTION

    ERRORLESS|Exercise NCERT BASED QUESTIONS (Energy of Simple Harmonic Motion)|18 Videos

  • SIMPLE HARMONIC MOTION

    ERRORLESS|Exercise Assertion & Reason|15 Videos

  • ROTATIONAL MOTION

    ERRORLESS|Exercise Assertion & Reason|25 Videos

  • SURFACE TENSION

    ERRORLESS|Exercise ASSERTION & REASON|11 Videos

Similar Questions

Explore conceptually related problems

The maximum velocity of a particle executing simple harmonic motion is v. If the amplitude is doubled and the time period of oscillation decreased to 1/3 of its original value the maximum velocity becomes

The maximum velocity of a particle executing SHM is v. If its amplitude of oscillation is doubled and its time period is made half of its initial value, the maximum velocity of it will be

The maimum velocity of a particle, executing SHM with an amplitude 7 mm is 4.4 m/s. the period of oscillation is

The maximum velocity a particle, executing simple harmonic motion with an amplitude 7 mm, 4.4 m//s. The period of oscillation is.

If the maximum velocity and acceleration of a particle executing SHM are equal in magnitude the time period will be

If the maximum velocity and acceleration of a particle executing SHM are equal in magnitude, the time period will be

Amplitude of a particle executing SHM is a and its time period is T. Its maximum speed is

The maximum velocity of a particle performing a linear S.H.M. of amplitude 1.4 cm is 4.4 m//s . What is the period of S.H.M. ?

If a particle executing S.H.M. with amplitude A and maximum velocity vo, then its speed at displacement A/2 is

The maximum velocity of a particle executing SHM is 100cms^(-1) and the maximum acceleration is 157cms^(-2) determine the periodic time