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A particle executing SHM according to th...

A particle executing SHM according to the equation `x=5cos(2pit+(pi)/(4))` in SI units. The displacement and acceleration of the particle at t=1.5 s is

A

`-3.0m,100m//s^(2)`

B

`+2.54m,200m//s^(2)`

C

`-3.54m,140m//s^(2)`

D

`+3.55m,120m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`x(t)=5cos(2pit+(pi)/(4))" "[because cos (3pi+alpha)=-cosalpha]`
`x=5 cos (2pi xx1.5+(pi)/(4))=-5"cos"(pi)/(4)=(-5)/(sqrt2)=-3.54` m
`a=-omega^(2)x=-(2pi)^(2)(-3.54)=140m//s^(2)`.
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