The ration of kinetic energy to the potential energy of a particle executing SHM at a distance equal to half its amplitude , the distance being measured from its equilibrium position is

Options

A. `4:1`
B. `8:1`
C. `3:1`
D. `2:1`

Answer

C

Explanation

`(KE)/(PE)=((1)/(2)momega^(2)(A^(2)-y^(2)))/((1)/(2)momega^(2)y^(2))=(A^(2)-((A)/(2))^(2))/(((A)/(2))^(2))=(3A^(2))/(4)xx(4)/(A^(2))`
`=3:1`.