The variation of potential enegy of harmonic oscillator is as shown in figure. The spring constant is

Options

A. `1xx10^(2)N//m`
B. `150N//m`
C. `0.667xx10^(2)N//m`
D. `3xx10^(2)N//m`

Answer

B

Explanation

`(PE)_("Total")=0.04J`
Resting PE=0.01 J
Maximum KE=0.04-0.01=0.03 J
`implies 0.03=(1)/(2)momega^(2)A^(2)=(1)/(2)kA^(2)`
`0.03=(1)/(2)xxk((20)/(1000))^(2) implies k=150N//m`.