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The total energy of a particle executing...

The total energy of a particle executing S.H.M. is proportional to

A

Displacement from equilibrium position

B

Frequency of oscillation

C

Velocity in equilibrium position

D

Square of amplitude of motion

Text Solution

Verified by Experts

The correct Answer is:
D
`E=(1)/(2)KA^(2)=(1)/(2)momega^(2)A^(2)` i.e. `Eprop A^(2)`.
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