The total energy of the body excuting `S.H.M.` is `E` . Then the kinetic energy when the displacement is half of the amplitude, is

Options

A. `E/2`
B. `E/4`
C. `(3E)/4`
D. `(sqrt3)/(4)E`

Answer

C

Explanation

`E=(1)/(2)momega^(2)A^(2)`
`KE=(1)/(2)momega^(2)(A^(2)-x^(2))`
At `x=(A)/(2)," "KE=(1)/(2)momega^(2)A^(2)((3)/(4))=(3)/(4) E`.