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The potential energy of a simple harmoni...

The potential energy of a simple harmonic oscillator, when the particle is half way to its end pint is

A

`1/8` E

B

`1/4` E

C

`1/2` E

D

`2/3` E

Text Solution

Verified by Experts

The correct Answer is:
B
`(PE)/(E)=((1)/(2)momega^(2)x^(2))/((1)/(2)momega^(2)A^(2))=(A^(2))/(4)xx(1)/(A^(2))`
`implies PE =(E)/(4)`.
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