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The period of oscillation of a simple pe...

The period of oscillation of a simple pendulum of constant length at earth surface is T. Its period inside a mine is C

A

Greater than T

B

Less than T

C

Equal to T

D

Cannot be compared

Text Solution

Verified by Experts

The correct Answer is:
A
As inside the mine g decreases
`T=2pisqrt((l)/(g))`, hence T increases.
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