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A man measures the period of a simple pe...

A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. if the lift accelerates upwards with an acceleration g/4, then the period of the pendulum will be

A

T

B

`T/4`

C

`(2T)/(sqrt5)`

D

`2Tsqrt5`

Text Solution

Verified by Experts

The correct Answer is:
C
`g_("eff")=g+(g)/(4)=(5g)/(4)`
`T=2pisqrt((l)/(g_("eff")))=2pisqrt((l)/((5)/(4)g))implies T.=(2T)/(sqrt5)`
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