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There is a simple pendulum hanging from ...

There is a simple pendulum hanging from the ceiling of a lift. When the lift is stand still, the time period of the pendulum is T . If the resultant acceleration becomes `g//4` ,then the new time period of the pendulum is

A

0.8 T

B

0.25 T

C

2 T

D

4 T

Text Solution

Verified by Experts

The correct Answer is:
C

`Tprop (1)/(sqrtg)`
`implies (T__(1))/(T)=sqrt((g)/(g_(1)))=sqrt((g)/(g//4))`
`implies T_(1)=2T`.
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