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A simple pendulum hanging from the ceili...

A simple pendulum hanging from the ceiling of a stationary lift has a time period T 1 . When the lift moves downward with constant velocity, the time period is T2, then

A

`T_(2)` is infinity

B

`T_(2) gt T_(1)`

C

`T_(2) lt T_(1)`

D

`T_(2) = T_(1)`

Text Solution

Verified by Experts

The correct Answer is:
D
As `Tprop(1)/(sqrtg)`
Since, v=constant, a=0
Hence, g does not change
`therefore T_(1)=T_(2)`.
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