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if a boby is released into a tunal dug across the diameter of earth, it executes simple harmonic motoin with time period

A

`T=2pisqrt((R_(e))/(g))`

B

`T=2pisqrt((2R_(e))/(g))`

C

`T=2pisqrt((R_(e))/(2g))`

D

`T=2` seconds

Text Solution

Verified by Experts

The correct Answer is:
A

Length of pendulum=`R_(e)`
`therefore T=2pisqrt((R_(e))/(g))`.
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