A simple pendulum is set up in a trolley which moves to the right with an acceleration a on a horizontal plane. Then the thread of the pendulum in the mean position makes an angle `theta` with the vertical

Options

A. `"tan"^(-1)(a)/(g)` in the forward direction
B. `"tan"^(-1) (a)/(g)` in the backward direction
C. `"tan"^(-1)(g)/(a)` in the backward direction
D. `"tan"^(-1)(g)/(a)` in the forward direction

Answer

B

Explanation

`tantheta=(ma)/(mg)=(a)/(g)`
`implies theta=tan^(-1)((a)/(g))`
in the backward direction.