A particle executes simple harmonic motion between `x=-A and x=+A`. The time taken for it to go from 0 to A/2. is `T_(1)` and to go from A/2 to A is `T_(2)`. Then:

Options

A. `T_(1) lt T_(2)`
B. `T_(1) gt T_(2)`
C. `T_(1)=T_(2)`
D. `T_(1)=2T_(2)`

Answer

A

Explanation

`x=Asinomegat`
for `x=A//2," "(A)/(2)=AsinomegaT_(1) implies T_(1)=(pi)/(6omega)`
for `x=A," "Asinomega(T_(1)+T_(2))=A implies T_(1)+T_(2)=(pi)/(2omega)`
`T_(2)=(pi)/(2omega)-T_(1)=(pi)/(3omega)` i.e., `T_(2) gt T_(1)`.