A mass of 4 kg suspended from a spring of spring constant `800 Nm^(-1)` executes simple harmonic oscillations. If the total energy of the oscillator is 4 J, the maximum acceleration (in `ms^(-2)`) of the mass is

Options

A. 5
B. 15
C. 45
D. 20

Answer

D

Explanation

Since. Total energy-
`E=(1)/(2)kA^(2)`
`implies A^(2)=(4xx2)/(800)=(1)/(100) implies A=0.1m`
maximum acceleration-
`a_(max)=omega^(2)A=(k)/(m)`A
`implies a_(max)=(800)/(4)xx0.01=20m//s^(2)`