A mass m is suspended by means of two coiled springs which have the same length in unstretched condition as shown in figure. Their force constants are `k_(1) and k_(2)` respectively. When set into vertical vibrations, the period will be

Options

A. `2pi sqrt(((m)/(k_(1)k_(2))))`
B. `2pisqrt(m((k_(1))/(k_(2))))`
C. `2pisqrt(((m)/(k_(1)-k_(2))))`
D. `2pisqrt(((m)/(k_(1)+k_(2))))`

Answer

D

Explanation

Since, `k_(eq)=k_(1)+k_(2)`
`T=2pisqrt((m)/(k_(1)+k_(2)))`.