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A spring is stretched by 5cm by a force 10N. The time period of the oscillations when a mass of 2Kg is suspended by it is

A

6.28 s

B

3.14 s

C

0.628 s

D

0.0628 s

Text Solution

Verified by Experts

The correct Answer is:
C
`F=kx implies k=(F)/(x)`
`k=(10)/(0.05)=200(N)/(m)`
`T=2pisqrt((m)/(k))`
`T=2pisqrt((2)/(200))=(2pi)/(10)=0.628sec`.
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