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An AC supply gives 30 V(rms)which passes...

An `AC` supply gives `30 V_(rms)`which passes through a `10 Omega` resistance. The power dissipated in it is

A

`90 sqrt(2)` W

B

90W

C

`45 sqrt(2) W`

D

45W

Text Solution

Verified by Experts

The correct Answer is:
B
Power `(P) = ((V_(rms))^(2))/(R) = ((30)^(2))/(10)`
P = 90 watt
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