An alternating voltage given as, `V=100sqrt(2)sin100t` V is applied to a capacitor of `1muF`. The current reading of the ammeter will be equal to ................ mA.

Options

A. 10
B. 20
C. 40
D. 80

Answer

A

Explanation

`X_(C) = (1)/(omega c) = (1)/( 2 pi f C)`
`= (1)/(100 xx 10 ^(-6)) = 10^(4) Omega `
Cureent `(I_(rms)) = (V_(rms))/(X_(C)) = (100 sqrt(2))/( sqrt(2) xx 10 ^(4)) = 10 ^(-2) A `
`rArr I_(rms) = 10 mA`