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An alternating emf = 220 sqrt(2) sin 10...

An alternating emf = `220 sqrt(2) sin ` 100 t V is applied to a capacitor `1 mu F ` . The current flowing through the capacitor is

A

22mA

B

12mA

C

32mA

D

42mA

Text Solution

Verified by Experts

The correct Answer is:
A
`e_(rms) = (220 sqrt(2))/( sqrt(2)) = 220 `
`X_(C) = (1)/(omega C) = (1)/(100 xx 1 xx 10 ^(-6)) = 10000 Omega `
`I_(rms) = (e_(rms))/(X_(C)) = (220)/( 10000) = 22 mA `
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